Math, asked by abishekjose6, 8 months ago

[(√2401+√625)-(29+5)]÷4?½ plz solve this question dut step by step image send​

Answers

Answered by sahil4561
3

Answer:

10 if it is 4 and 20 if it is 4 raise to power 1/2 in your question

Step-by-step explanation:

here 2401 is root of 49

and 625 is root of 25

by solving all this is answer

Attachments:
Answered by apal06793
1

Answer:

 \sqrt{} 2401 +  \sqrt{625 }  - (29 - 5) \div 4  \\ (49 + 25) - 34 \div 4 \\ 40 \div 4 = 10

Step-by-step explanation:

plz make a brainlist

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