Math, asked by rimshaaaa84, 7 months ago

(243)^_2/3 (32)^-1/5 /√(196)^-1​

Answers

Answered by anjukrishusachin
1

Step-by-step explanation:

 \frac{ {243}^{ \frac{ - 2}{3} }  \times  {32}^{ \frac{ - 1}{5} } }{ \sqrt{ {196}^{ - 1} } }  \\  =  \frac{ \sqrt{ {196}^{1} } }{ {243}^{ \frac{2}{3} }  \times  {32}^{ \frac{1}{5} } }  \\  =  \frac{14}{ \sqrt[3]{ {243}^{2} } \times \sqrt[5]{ {32}^{1} } }  \\  =  \frac{14}{\sqrt[3]{ {243} \times 243 } \times  \sqrt[5]{2 \times 2 \times 2 \times 2 \times 2} }  \\  =  \frac{14}{ \sqrt[3]{3 \times 3 \times 3 \times 3 \times 3 \times 3 \times 3 \times 3 \times 3 \times 3}  \times 2}  \\  =  \frac{14}{3 \times 3 \times 3 \times 2 \times  \sqrt{3} }  \\  =  \frac{7}{27 \sqrt{3} }  \\ agar \: 243 \: ki \: power \:  -  \frac{3}{2}  \: ho \: to \: answer \: kuch \: aur \: ho \: skta \: hai \\  \\  \\

hope it helps you

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