Question

(243)s power x+1=(243)s power -5 then find the value of x

Answer 1

SOLUTION

GIVEN

$\sf{ {(243)}^{x + 1} = {(243)}^{ - 5} }$

TO DETERMINE

The value of x

CONCEPT TO BE IMPLEMENTED

We are aware of the formula on indices that :

If a is a non zero real number then

$\sf{ {a}^{m} = {a}^{n} \: \: implies \: \: m = n}$

EVALUATION

Here it is given that

$\sf{ {(243)}^{x + 1} = {(243)}^{ - 5} }$

Now Comparing both sides we get

$\sf{ x + 1 = - 5 }$

$\sf{ \implies \: x = - 5 - 1 }$

$\sf{ \implies \: x = - 6 }$

FINAL ANSWER

Hence the required value of x = - 6

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Answer 2

Answer:

SOLUTION

SOLUTIONGIVEN

SOLUTIONGIVEN\sf{ {(243)}^{x + 1} = {(243)}^{ - 5} }(243)

SOLUTIONGIVEN\sf{ {(243)}^{x + 1} = {(243)}^{ - 5} }(243) x+1

SOLUTIONGIVEN\sf{ {(243)}^{x + 1} = {(243)}^{ - 5} }(243) x+1 =(243)

SOLUTIONGIVEN\sf{ {(243)}^{x + 1} = {(243)}^{ - 5} }(243) x+1 =(243) −5

SOLUTIONGIVEN\sf{ {(243)}^{x + 1} = {(243)}^{ - 5} }(243) x+1 =(243) −5

SOLUTIONGIVEN\sf{ {(243)}^{x + 1} = {(243)}^{ - 5} }(243) x+1 =(243) −5 TO DETERMINE

SOLUTIONGIVEN\sf{ {(243)}^{x + 1} = {(243)}^{ - 5} }(243) x+1 =(243) −5 TO DETERMINEThe value of x

SOLUTIONGIVEN\sf{ {(243)}^{x + 1} = {(243)}^{ - 5} }(243) x+1 =(243) −5 TO DETERMINEThe value of xCONCEPT TO BE IMPLEMENTED

SOLUTIONGIVEN\sf{ {(243)}^{x + 1} = {(243)}^{ - 5} }(243) x+1 =(243) −5 TO DETERMINEThe value of xCONCEPT TO BE IMPLEMENTEDWe are aware of the formula on indices that :

SOLUTIONGIVEN\sf{ {(243)}^{x + 1} = {(243)}^{ - 5} }(243) x+1 =(243) −5 TO DETERMINEThe value of xCONCEPT TO BE IMPLEMENTEDWe are aware of the formula on indices that :If a is a non zero real number then

SOLUTIONGIVEN\sf{ {(243)}^{x + 1} = {(243)}^{ - 5} }(243) x+1 =(243) −5 TO DETERMINEThe value of xCONCEPT TO BE IMPLEMENTEDWe are aware of the formula on indices that :If a is a non zero real number then\sf{ {a}^{m} = {a}^{n} \: \: implies \: \: m = n}a

SOLUTIONGIVEN\sf{ {(243)}^{x + 1} = {(243)}^{ - 5} }(243) x+1 =(243) −5 TO DETERMINEThe value of xCONCEPT TO BE IMPLEMENTEDWe are aware of the formula on indices that :If a is a non zero real number then\sf{ {a}^{m} = {a}^{n} \: \: implies \: \: m = n}a m

SOLUTIONGIVEN\sf{ {(243)}^{x + 1} = {(243)}^{ - 5} }(243) x+1 =(243) −5 TO DETERMINEThe value of xCONCEPT TO BE IMPLEMENTEDWe are aware of the formula on indices that :If a is a non zero real number then\sf{ {a}^{m} = {a}^{n} \: \: implies \: \: m = n}a m =a

SOLUTIONGIVEN\sf{ {(243)}^{x + 1} = {(243)}^{ - 5} }(243) x+1 =(243) −5 TO DETERMINEThe value of xCONCEPT TO BE IMPLEMENTEDWe are aware of the formula on indices that :If a is a non zero real number then\sf{ {a}^{m} = {a}^{n} \: \: implies \: \: m = n}a m =a n

SOLUTIONGIVEN\sf{ {(243)}^{x + 1} = {(243)}^{ - 5} }(243) x+1 =(243) −5 TO DETERMINEThe value of xCONCEPT TO BE IMPLEMENTEDWe are aware of the formula on indices that :If a is a non zero real number then\sf{ {a}^{m} = {a}^{n} \: \: implies \: \: m = n}a m =a n impliesm=n

SOLUTIONGIVEN\sf{ {(243)}^{x + 1} = {(243)}^{ - 5} }(243) x+1 =(243) −5 TO DETERMINEThe value of xCONCEPT TO BE IMPLEMENTEDWe are aware of the formula on indices that :If a is a non zero real number then\sf{ {a}^{m} = {a}^{n} \: \: implies \: \: m = n}a m =a n impliesm=nEVALUATION

SOLUTIONGIVEN\sf{ {(243)}^{x + 1} = {(243)}^{ - 5} }(243) x+1 =(243) −5 TO DETERMINEThe value of xCONCEPT TO BE IMPLEMENTEDWe are aware of the formula on indices that :If a is a non zero real number then\sf{ {a}^{m} = {a}^{n} \: \: implies \: \: m = n}a m =a n impliesm=nEVALUATIONHere it is given that

SOLUTIONGIVEN\sf{ {(243)}^{x + 1} = {(243)}^{ - 5} }(243) x+1 =(243) −5 TO DETERMINEThe value of xCONCEPT TO BE IMPLEMENTEDWe are aware of the formula on indices that :If a is a non zero real number then\sf{ {a}^{m} = {a}^{n} \: \: implies \: \: m = n}a m =a n impliesm=nEVALUATIONHere it is given that\sf{ {(243)}^{x + 1} = {(243)}^{ - 5} }(243)

x+1

=(243)

=(243) −5

=(243) −5

=(243) −5 Now Comparing both sides we get

=(243) −5 Now Comparing both sides we get\sf{ x + 1 = - 5 }x+1=−5

=(243) −5 Now Comparing both sides we get\sf{ x + 1 = - 5 }x+1=−5\sf{ \implies \: x = - 5 - 1 }⟹x=−5−1

=(243) −5 Now Comparing both sides we get\sf{ x + 1 = - 5 }x+1=−5\sf{ \implies \: x = - 5 - 1 }⟹x=−5−1\sf{ \implies \: x = - 6 }⟹x=−6

=(243) −5 Now Comparing both sides we get\sf{ x + 1 = - 5 }x+1=−5\sf{ \implies \: x = - 5 - 1 }⟹x=−5−1\sf{ \implies \: x = - 6 }⟹x=−6FINAL ANSWER

=(243) −5 Now Comparing both sides we get\sf{ x + 1 = - 5 }x+1=−5\sf{ \implies \: x = - 5 - 1 }⟹x=−5−1\sf{ \implies \: x = - 6 }⟹x=−6FINAL ANSWERHence the required value of x = - 6

=(243) −5 Now Comparing both sides we get\sf{ x + 1 = - 5 }x+1=−5\sf{ \implies \: x = - 5 - 1 }⟹x=−5−1\sf{ \implies \: x = - 6 }⟹x=−6FINAL ANSWERHence the required value of x = - 6━━━━━━━━━━━━━━━━