Question

243217635_132...
2. In the figure given, what are the values
of Za?
ca
46
20
В
Nuus
(a) 92°
(c) 20°
(b) 18°
(d) 15°

Answer 1

Answer:

18° is correct answer to this

Answer 2

Solution :-

In ∆ACE we have,

→ AC = CE

→ ∠AEC = 46°

So,

→ ∠CAE = ∠AEC { Angle opposite to equal sides are equal in measure .}

then,

→ ∠CAE = 46°

therefore,

→ ∠ACB = ∠CAE + ∠AEC { Exterior angle is equal to sum of opposite interior angles .}

→ ∠c = 46° + 46°

→ ∠c = 92° ----------- Eqn.(1)

Similarly, In ∆ABD we have,

→ AB = BD { It must be given. }

→ ∠ADB = 35°

So,

→ ∠ADB = ∠DAB { Angle opposite to equal sides are equal in measure .}

then,

→ ∠DAB = 35°

therefore,

→ ∠ABC = ∠ADB + ∠DAB { Exterior angle is equal to sum of opposite interior angles .}

→ ∠b = 35° + 35°

→ ∠c = 70° ----------- Eqn.(2)

Now, in ∆ABC,

→ ∠a + ∠b + ∠c = 180° { By angle sum property .}

putting values from Eqn.(1) and Eqn.(2),

→ ∠a + 70° + 92° = 180°

→ ∠a + 162° = 180°

→ ∠a = 180° - 162°

→ ∠a = 18° (b) (Ans.)

Learn more :-

In the figure along side, BP and CP are the angular bisectors of the exterior angles BCD and CBE of triangle ABC. Prove ∠BOC = 90° - (1/2)∠A .

brainly.in/question/32333207