Question

24a2-54b2 factorize conpketely​

Answer 1

Answer:

$24 {a}^{2} - 54 {b}^{2} \\ = 6 \times 4 {a}^{2} - 6 \times 9 {b}^{2} \\ = 6(4 {a}^{2} - 9 {b}^{2}) \\ = 6 \{(2a)^{2} - (3b)^{2} \} \\ = 6(2a + 3b)(2a - 3b)$

Answer 2

$6(2a + 3b)(2a - 3b)$

GIVEN:-

$24 {a}^{2} - 54 {b}^{2}$

TO FIND:- Factorize completely.

SOLUTION:-

• In mathematics, factorization or factoring comprise writing a number or another mathematical subject as a product of various factors, mostly smaller or simpler subjects of the same kind.

$24 {a}^{2} - 54 {b}^{2}$

By taking breaking both

$= (6 \times 4 {a}^{2} ) - (6 \times 9 {b}^{2} )$

By taking 6 common

$= 6(4 {a}^{2} - 9{b}^{2} ) \\ = 6( {(2a)}^{2} - ( {3b})^{2} )$

By applying the a²-b² formula = (a+b) (a-b)

$= 6(2a + 3b)(2a - 3b)$

Hence, $6(2a + 3b)(2a - 3b)$

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