Question

24a³+81b³ factories​

Answer 1

3(8a³+27b³) =3(2a³+3b³)

3(2a+3b) (2a²-2a×3b+3b²)

3(2a+3b) (4a²-6ab+9b²)

Answer 2

Answer:

$24 {a}^{3} + 81 {b}^{3} \\ = 3(8 {a}^{3} + 27 {b}^{3} ) \\ = 3( {(2a)}^{3} + {(3b)}^{3} ) \\ = 3(2a + 3b)( {(2a)}^{2} - (2a)(3b) + {(3b)}^{2} ) \\ = 3(2a + 3b)(4 {a}^{2} - 6ab + 9 {b}^{2} )$