Question

24g of carbon is treated with 72 g of o2 to form co2 a)idenyify the limiting reagent b)find the number of molecule of co2 formed ​

Answer 1

Answer:

a) The limiting reagent is C.

b) The number of molecules of $CO_{2}$ formed is $12.044*10^{23}$.

Explanation:

The balanced chemical equation for the reaction can be written as:

$C + O_{2}$ → $CO_{2}$

a) Number of moles of C= given mass/molar mass

Given mass = 24 g

Molar mass = 12 g/mol

Number of moles of C = $\frac{24}{12}$

                                     = 2 moles

Number of moles of $O_{2}$ = given mass/molar mass

Given mass = 72 g

Molar mass = 32 g/mol

Number of moles of $O_{2}$ = $\frac{72}{32}$

                                       = 2.25 moles

From the balanced chemical equation, 1:1 ratio of C and $O_{2}$ are required to produce 1 mole of $CO_{2}$.

So the limiting reagent here is C since only 2 moles of C is available to react with 2.25 moles of $O_{2}$.

b) The limiting reagent here is C.

Number of moles of $CO_{2}$ formed = Number of moles of C

                                                       = 2 moles

Number of molecules of $CO_{2}$ formed = $2*6.022*10^{23}$

                                                              = $12.044*10^{23}$ molecules.