Chemistry, asked by riduvarshinir2207, 7 months ago

24g Of carbon react with 40g O2 to produce a mixture of CO and CO2 leaving behind no reactants.The ratio of CO and CO2 produced is

Answers

Answered by priyashakthi635
2

Answer:

ANSWER

Given:

Moles of C =

12

12

=1

Moles of O

2

=

32

20

=0.625

Reaction:

Let the moles of oxygen which react with C to form CO

2

be x

2C + O

2

→ 2CO

1−x (1−x)/2 1−x

C+O

2

→CO

2

x x x

We have, (1−x)/2+x=0.625

Hence, x=0.25

So, moles of carbon dioxide is equal to 0.25 and moles of carbon monoxide is equal to 0.75 .

So, mass of CO produced is 21 g and mass of CO

2

produced is 11 g.

Answered by sadiaanam
0

Answer: The ratio of CO to CO2 is approximately 1.57:0.73, which can be simplified to 2.15:1, or approximately 2:1 .

Explanation:

To determine the ratio of CO and CO2 produced when 24g of carbon reacts with 40g of O2, we need to first find the limiting reagent, which is the reactant that gets completely used up in the reaction.

To do this, we need to compare the amounts of CO and CO2 that can be produced from 24g of carbon and 40g of O2. We can use the balanced chemical equation for the combustion of carbon to determine the amounts of CO and CO2 that can be produced:

C + O2 -> CO2 (1)

C + 1/2 O2 -> CO (2)

Using the equation (1), we can calculate that 24g of carbon would produce 88g of CO2.

Using the equation (2), we can calculate that 24g of carbon would produce 44g of CO.

Next, we need to calculate the amount of O2 required to produce these amounts of CO and CO2. The equation (1) requires 32g of O2 to produce 88g of CO2, and the equation (2) requires 16g of O2 to produce 44g of CO.

Since we have 40g of O2 available, which is greater than the amount required for either equation, O2 is not the limiting reagent. The limiting reagent is carbon because it requires 24g of carbon to produce 44g of CO, which is less than the amount required to produce 88g of CO2.

Therefore, the reaction will consume all 24g of carbon to produce 44g of CO and 32g of CO2.

The ratio of CO to CO2 is the ratio of the number of moles of each product produced. Using the molar masses of CO and CO2, we can convert the masses to moles:

44g CO = 44/28 = 1.57 moles CO

32g CO2 = 32/44 = 0.73 moles CO2

Therefore, the ratio of CO to CO2 is approximately 1.57:0.73, which can be simplified to 2.15:1, or approximately 2:1 (to the nearest whole number). So, for every two moles of CO produced, one mole of CO2 is produced.

Learn more about Combustion :

https://brainly.in/question/49989637

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