Question

24g of carbon reacts with some oxygen to make 88 grams of carbon dioxide. find out how much oxygen must have been used​

Answer 1

the reactant mass is equal to product mass.

hence,

24+X=88

X=88-24

X=64 grams of oxygen is needed to form 88 grams of carbon dioxide with 24 grams of carbon.

Answer 2

24 g of oxygen reacts with 64g of oxygen to give 88 grams of carbon dioxide.

• The chemical equation involved in the reaction between carbon and oxygen is as follows:

$C+O_2\rightarrow CO_2$

• We know that the mass of the reactant is equal to the mass of the product. In the given condition, the mass of carbon and carbon dioxide is given as 24g and 88g respectively.

• Let the mass of oxygen be X.

⇒ 24 + X = 88

∴X = 88 - 24

X = 64

• When X value is substituted in the below equation it gives as follows:

24 + 64 = 88

88 = 88

• Thus the mass of the reactant side is equal to the mass of the product side. Hence, 24 g of oxygen reacts with 64g of oxygen to give 88 grams of carbon dioxide.

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