Question

24is divided into two parts such that 6 times the first part exceeds 4 times the second part by 4 find the first part ?

Answer 1

Number=24

24 is Divided into 2 parts

Let First Part=x

Then Second Part=24-x

A/Q

6 times First Part(x) Increase 4 times second part(24-x) by 4

MEANS

First part×6=Second Part ×4+4

A/q

6x+4=4(24-x)+4

6x=96-4x+4

6x+4x=100

10x=100

x=100/10

x=10

First Part=x=10

Second Part=24-x=24-10=14

$\boxed{\mathbf{\huge{First \:Part=10}}}$

Answer 2

Given - 24 is divided into two parts such that 6 times the first part exceeds 4 times the second part by 4

Find - First part

Solution - Let the first part be x. So, the second part will be (24 - x).

Now, as per given information -

6x = 4(24 - x) + 4

Solving the mentioned equation to find the value of x-

6x = 96 - 4x + 4

6x + 4x = 96 + 4

Performing addition to find the value of x-

10x = 100

Performing division to find the value of x -

x = 10

First part = 10

Second part = 24 - x

Second part = 24 - 10

Second part = 14

Therefore, first part is 10.