Question

24x^2-41x+12=0 please solve it

Answer 1

Hii..

➡️ Answer is in attachment.

hope this helps :)

Answer 2

24x^2-41x+12=0
b^2-4ac=41^2-4×24×12=1681-1152=529

$x = \frac{ - b + or - \sqrt{ {b}^{2} - 4ac} }{2a}$
$x = \frac{41 + - \sqrt{529} }{48 }$
$x = \frac{41 + - 23}{48}$

$x = \frac{64}{48} or \: x = \frac{18}{48}$
X=4/3 or 3/8 (after simplifying)