Question

25.0 ml of HCI solution gave, on reaction with excess AgNO, solution 2.125g of AgCl. The
molarity of HCl solution is
(A) 0.25
(B) 0.6
(C) 1.0
(D) 0.75​

Answer 1

Given:

• Volume of HCl (V) = 25 mL
• Mass 0f AgCl produced (w) = 2.125 g
• Molar mass of AgCl (Mm) = 143.5 g/mol

To find;

The molarity of HCl.

Solution:

• Moles of AgCl produced = w/Mm = 0.0148
• Each mole of HCl on reacting with AgNO₃ produces one mole of AgCl.
• Moles of HCl (n) = moles of AgCl produced = 0.0148

• Molarity 0f HCl = n*1000/V = 14.8/25 = 0.59 ≈ 0.6 M

Answer:

The molarity of HCl = 0.6 M.