Question

25.0 ml of HCL solution gave ,on reaction with exess AgNO3 solutions 2.125 g agcl.the normally of hcl??​

Answer 1

Given:

Volume of HCl = 25.0 ml

Mass of AgCl = 2.125

To find:

Normality of HCl

Solution:

• We know that, Molecular weight of AgCl = 143

• Now, moles of AgCl = 2.125​ / 143 = 0.01486

• Also, number of moles AgCl = number of moles of HCl = 0.01486

• Now, molarity of HCl solution can be calculated as-

        = Number of moles of HCl​ / Volume of solution in litres

        = 0.01486 / (25 / 1000)

        = 0.6 M

• Now, the normality of HCl = Molarity x (number of hydrogen ions)

                                                    = 0.6 x 1

                                                    = 0.6

• Thus, the normality of HCl is 0.6 N