25. 1 atom of an element weighs 1.792x10-22 g. The
atomic weight of element is
(1) 107.92
(2) 17.92
(3) 1.192
(4) 64
Answers
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Answered by
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Answer:
Explanation:
Weight of the atom of an element = 1.792x10-22 (Given)
Let the atomic mass of the atom be = x
x grams of the element contains Avogadro number of atoms = 6 × 10^23 atoms
Weight of one mole of atoms = atomic weight
Where one mole = 6.022 × 10^23 atoms
Weight of one atom = x/(6 × 10^23)
= 1.8 × 10^-22
Thus, the atomic weight will be -
x = 6 × 10^23 × 1.8 × 10^-22 = 107.9 = 108 g/mole
Therefore, the atomic mass of the element is 108 g/mole.
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