Question

25. 1 atom of an element weighs 1.792x10-22 g. The
atomic weight of element is
(1) 107.92
(2) 17.92
(3) 1.192
(4) 64​

Answer 1

Answer:

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Answer 2

Answer:

Explanation:

Weight of the atom of an element = 1.792x10-22 (Given)

Let the atomic mass of the atom be = x

x grams of the element contains Avogadro number of atoms = 6 × 10^23 atoms

Weight of one mole of atoms = atomic weight  

Where one mole = 6.022 × 10^23 atoms  

Weight of one atom = x/(6 × 10^23)

= 1.8 × 10^-22

Thus, the atomic weight will be -

x = 6 × 10^23 × 1.8 × 10^-22​ = 107.9 = 108 g/mole

Therefore, the atomic mass of the element is 108 g/mole.