☆+☆+○=25,○+○+□=12,□+□+☆=5,☆+○+□=? find the number
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For convenience
let star be x , circle be y , rectangle be z
so , x + x + y = 25⇒ 2x + y =25 eq.1
y + y + z = 12 ⇒ 2y + z =12 eq.2
z + z + x = 5 ⇒ 2z + x =5 eq.3
from eq.1
y = 25 - 2x
put this value in eq. 2
2(25 - 2x) + z =12 ⇒ 50 - 4x + z = 12 ⇒ 4x - z = 38 eq . 4
now , z = 4x - 38
put this value in eq. 3
2(4x - 38) + x = 5⇒ 8x - 76 + x = 5 ⇒ 9x = 5 + 76 = 81
x = 9 , put this in eq. 4
4x9 - z = 38 ⇒ z = 36 - 38 = -2
z = -2 , put this in eq. 2
2y + (-2) = 12 ⇒ 2y = 12 - 2 = 10 ⇒ y = 5
y= 5
hence , x= 9 , y =5 and z = -2
so , x + y + z = 9+5-2 = 14 - 2 = 12
so , answer is 12
plzzz mark brainliest
let star be x , circle be y , rectangle be z
so , x + x + y = 25⇒ 2x + y =25 eq.1
y + y + z = 12 ⇒ 2y + z =12 eq.2
z + z + x = 5 ⇒ 2z + x =5 eq.3
from eq.1
y = 25 - 2x
put this value in eq. 2
2(25 - 2x) + z =12 ⇒ 50 - 4x + z = 12 ⇒ 4x - z = 38 eq . 4
now , z = 4x - 38
put this value in eq. 3
2(4x - 38) + x = 5⇒ 8x - 76 + x = 5 ⇒ 9x = 5 + 76 = 81
x = 9 , put this in eq. 4
4x9 - z = 38 ⇒ z = 36 - 38 = -2
z = -2 , put this in eq. 2
2y + (-2) = 12 ⇒ 2y = 12 - 2 = 10 ⇒ y = 5
y= 5
hence , x= 9 , y =5 and z = -2
so , x + y + z = 9+5-2 = 14 - 2 = 12
so , answer is 12
plzzz mark brainliest
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