Question

{25×16÷(60÷15)- 4×(77- 62)}÷(20×6÷3)

Answer 1

♧♧HERE IS YOUR ANSWER♧♧

We apply BODMAS rule :

{25×16÷(60÷15)- 4×(77- 62)}÷(20×6÷3)

= {25×16÷4 - 4×(77- 62)}÷(20×2)

= {25×4 - 4×(77- 62)}÷(20×2)

= {100 - 4×(77- 62)}÷40

= {100 - 4×15}÷40

= {100 - 60}÷40

= 40÷40

= 1

♧♧HOPE THIS HELPS YOU♧♧

Answer 2

Answer:

{25×16÷(60÷15)- 4×(77- 62)}÷(20×6÷3) = 1

Explanation:

As per the question:

Given That:

{25×16÷(60÷15)- 4×(77- 62)}÷(20×6÷3)

To Find:

we have to find the answer of the above question.

Step-by-step explanation:

We  can apply BODMAS rule to solve :

{25×16÷(60÷15)- 4×(77- 62)}÷(20×6÷3)

= {25×16÷4 - 4×(77- 62)}÷(20×2)

= {25×4 - 4×(77- 62)}÷(20×2)

= {100 - 4×(77- 62)}÷40

= {100 - 4×15}÷40

= {100 - 60}÷40

= 40÷40

= 1

Therefore, the answer of {25×16÷(60÷15)- 4×(77- 62)}÷(20×6÷3) = 1.

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