Math, asked by nidhi4deshwal, 8 months ago

{(25)273} divide(837

Answers

Answered by cdaksh04

Answer:

The two equations x^2 + y^2-12x-6y - 4 = 0 and x^2 + y^2 - 4x-12y - k = 0 have simultaneous real solutions (x,y) if a<=k<=b and no other value of k then a+b is

Step-by-step explanation:

The two equations x^2 + y^2-12x-6y - 4 = 0 and x^2 + y^2 - 4x-12y - k = 0 have simultaneous real solutions (x,y) if a<=k<=b and no other value of k then a+b is

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