Question

25
2
Find the value of 'K' for which the roots of the equation
4x212x+k are real and equal.
[ar
For what values of k shall the following equations have
infinitely many solutions?​

Answer 1

Answer:

K < -9

step-by-step explanation:

Given quadratic equation,

4x^2 - 12x - K = 0

According to the general form of a quadratic equation,

ax^2 + bx + c = 0

Here,

a = 4

b = -12

c = -K

Now,

we know that,

In a quadratic equation,

There will be no real roots only when the

Descriminant ( D) < 0

i.e.,

Descriminant is neagative.

A.T.Q

D < 0

=> b^2 - 4ac < 0

Putting the values of a, b and c

we get,

=> (-12)^2 - 4 × (4)×(-K) < 0

=> 144 + 16K < 0

=> 16K < -144

=> K < -144/16

=> K < -9

Hence, for no real roots,

the value of

K < -9

Answer 2

Answer:

K<-9 it is the answer