Question

25+[20-{2-(20 of 1/5÷1/8×1/16-8)}]

Answer 1

According to the BODMAS rule:
25+[20-{2-(4*8*1/6-8)}]
25+[20-{2-(2-8)}]
25+[20-{2-2+8}]
25+[20-2+2-8]
25-12
13
Ans=13

Answer 2

Answer:

13

Step-by-step explanation:

To solve the subsequent sign, we need to use BODMAS,

BODMAS rule says the sequence of the solving the question

B= bracket

O= of

D= Division

M= Multiply

A= addition

S= subtraction

Solve the bracket first

⇒ 25+[20-{2-(4*8*1/6-8)}]

⇒ 25+[20-{2-(2-8)}]

⇒ 25+[20-{2-2+8}]

⇒ 25+[20-2+2-8]

⇒ 25-12

⇒ 13

Hence the required answer is 13