Question

25 314
If one angle of triangle is 15º more than its second angle. The third angle is 25° mor
than double the second angle. Find the three angles of the triangle,​

Answer 1

Answer:

x = 35

Step-by-step explanation:

Let first angle be x

Second angle be x +15

Third angle = 2x +25

Sum of angle = 180

x + x + 15 + 2x + 25 = 180

4x + 40 = 180

x + 10 = 45

x = 35

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Answer 2

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✤ Required Answer:

✒ GiveN:

• First angle is 15° more than second angle.
• Third angle is 25° more than twice the second angle.

✒ To FinD:

• Find the measures of all three angles....?

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✤ How to solve?

Here, we can take the smallest angle as a variable and then framing the measure of rest angles in terms of the variable. Basically, What we are gonna do is, Solving the question by using one equation.

⚘ So, Let's solve this question...$.$

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✤ Solution:

We have,

• First angle 15° more than second angle.
• Third angle 25° more than twice of 2nd angle.

So, Clearly

➝ Second angle is the smallest of all.

Let second angle be x

Then, According to conditions,

• First angle = Second angle + 15°

➝ First angle = x + 15°

• Third angle = 2 × second angle + 25°

➝ Third angle = 2x + 25°

We know that,

Angles of a triangle add upto 180°

➝ 1st angle + 2nd angle + 3rd angle = 180°

➝ x + 15° + x + 2x + 25° = 180°

➝ 4x + 40° = 180°

➝ 4x = 140°

➝ x = 140°/4 = 35°

☀️ So, Our Required angles are:

• 1st angle = x + 15° = 50°
• 2nd angle = x = 35°
• 3rd angle = 2x + 25° = 70° + 25° = 95°

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