Question

25
33. For the generalized structure
BrCH2CHCICH2CHCICH2Br there exists what
number of stereoisomers?
6
ОООО
4​

Answer 1

Answer:

sorry i didn't understand your question

Answer 2

For the generalized structure $BrCH_{2}CH(CI)CH_{2}CH(CI)CH_{2}Br$, there exist 4 stereoisomers.

Given,

The generalized structure of a compound: $BrCH_{2}CH(CI)CH_{2}CH(CI)CH_{2}Br$ .

To Find,

The number of stereoisomers possible for the given compound.

Solution,

The method of finding the number of stereoisomers of the given compound is as follows -

We know when a carbon atom is attached to four different types of groups of atoms in an organic compound, that particular carbon atom is called an asymmetric carbon atom or chiral carbon atom.

We also know that for an organic compound if the compound has n numbers of chiral carbons, the number of stereoisomers of the compound will be $2^{n}$.

So in $BrCH_{2}CH(CI)CH_{2}CH(CI)CH_{2}Br$, we can observe the 2nd and 4th carbon atoms are attached to four different types of groups of atoms. So in this case, the number of chiral carbons is 2.

So the number of possible stereoisomers is $2^{2}=4$.

Hence, for the generalized structure $BrCH_{2}CH(CI)CH_{2}CH(CI)CH_{2}Br$, there exist 4 stereoisomers.

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