Math, asked by Amrudha, 8 months ago

25*5²*t^8/10³*t^3. ​

Answers

Answered by somveersingh881
3

\bold {\huge{\red{\underline{\underline{Answer:}}}}} \\ \frac{ 25 \times 5 {}^{2}  \times t {}^{8} }{10 {}^{3}  \times t {}^{3} } \\  =  \frac{5 {}^{2} \times 5 {}^{2} \times  t {}^{8}  }{(2 \times 5) {}^{3}  \times  {t}^{3}  }  \\  =  \frac{5 {}^{2  + 2}  \times  {t}^{8} }{2 {}^{3} \times 5 {}^{3} \times  {t}^{3}   }  \:  \:  \:  \: (a {}^{m}  \times a {}^{n}  = a {}^{m + n} ) \\  = 5 {}^{4}  \times  {t}^{8}  \times 2 { }^{ - 3}  \times 5 ^{ - 3}  \times  {t}^{ - 3}  \\   =5^{4+(-3)}×t^{8+(-3)}×2^{-3}  \\ =5^{4-3}×t^{8-3}× \frac{1}{8}    \:  \:  \:  \:  \:  \:  \: (x^{-n}=   \frac{1}{x^{n}}) \\ = \frac{ 5t^{5}}{8}

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