Question

25. A and B can do a piece of work in 10 days, B and C in 15
days and Cand Ain 20 days. They all work at it for 6 days,
and then A leaves, and B and C go on together for 4 days
more. If B then leaves, how long will take to complete
the work?

Answer 1

Step-by-step explanation:

The part of work A and B can do in aday is 1/10

The part of work B and C can do in aday is /15

1hecpart I of work C and Ai can do in aday i is 1/20

They all worked for 6days

So the part of work the all can do in aday is

2 (A + B+C ) Can do part of the work 1/10+1/20+ 1 /15 =( 6+3+4)/60 =13/60

So (A+B+C )Can do a part of the work in a day is 13/120

In 6 days they cover 6 ×13 /120

= 13/20

Balance of work is 1-- 13/20 =7/20

B and C together do part of work is day is 1/15

In 4 days B and C do part of WORK is 4/15

B LEAVES

BALANCE OF WORK =7/20 --4/15

=21-- 16 /60 =

5/60

=1/12

C HAS TO COMPLETE THE WORK OF 1/12

No of days C needs to complete the work is

1/12 /120 = 1/12 × 120 =10 days

C COMPLETES THE WORK IN 10 DAYAS

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