Question

25(a+b)²-49(a-b)² factorise by using identity​

Answer 1

make my answer the brailiest

Answer 2

GIVEN:-

Factorise 25(a+b)²-49(a-b)²

IDENTITY USED:-

${\large{\boxed{\rm{a^2-b^2=(a+b)(a-b)}}}}$

Now,

Let, (a+b) be x, (a-b) be y.......1

$\rm{25(a+b)^2-49(a-b)^2}$

Let's simplify it.

$\rm{5x^2-7y^2}$

$\rm{(5x+7y)(5x-7y)}$

$\rm{(5(a+b)+7(a-b))(5(a+b)-7(a-b))}$

$\rm{(5a+5b+7a-7b)(5a+5b-7a+7b)}$

$\rm{(12a-2b)(-2a+12b)}$

Some of the Useful identity

• $\rm{(a+b)^2=a^2+2ab+b^2}$

• $\rm{(a-b)^2=a^2-2ab+b^2}$

• $\rm{a^2+b^3=(a+b)(a^2-ab+b^2)}$.