Math, asked by sanjayt9031, 10 months ago

25(a+b)whole square-16(a-b)whole square​

Answers

Answered by Anonymous
51

\red {\huge {\underline{ \frak{Your \: answEr : }}}}

 \rightarrow \tt{25(a + b)^{2} - 16( {a - b)}^{2}  }

\rightarrow \tt{25( {a}^{2}  +  {b}^{2} + 2ab) - 16( {a}^{2} +  {b}^{2} - 2ab)  }

\rightarrow \tt{25 {a}^{2} + 25 {b}^{2} + 50ab - 16 {a}^{2}  - 16 {b}^{2}  + 32ab  }

 \large \green{\rightarrow \boxed{ \tt{9 {a}^{2} - 9 {b}^{2} + 82ab } }}

\huge{\red{\ddot{\smile}}}

Answered by lubna165
1

Answer:

25(a+b)^2-16(a-b)^2

Step-by-step explanation:

{[5(a+b)]^2}-{[4(a-b)]^2}

{[5a+5b]^2} - {[4a-4b]^2}

a^2-b^2=(a+b) (a-b)

(5a+5b+4a-4b)(5a+5b-4a+4b)

(9a+b)(a+9b)

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