Question

25. A can do a certain job i 12 days. B 60% more efficient than . Find the
by B to finish the job​

Answer 1

Assume that amount of work done is 1 unit

$so \: \frac{1}{12} \\ b \: \: has \: 60\% \: more \: than \: a \\ 60\% \: of \: \frac{1}{12} \: will \: be \: \frac{1}{20} \\ so \: \frac{1}{20} + \frac{1}{12} = \frac{1}{7.5}$

So 7.5 is the answer

#AnswerWithQuality

#BAL

Answer 2

Answer:

A can do work in 12 days

Time taken by A = 12 days

=> Work Done by A= 1/12

B is 60%more efficient

=>Work done by B is 60% more

work done by B is 160% more than A

=>Work Done by B =

$\frac{160}{100} \times \frac{1}{12} \\ \frac{16}{10} \times \frac{1}{12 }$

= 2/15

=>Time taken by B = 15/2 days

=7.5 days