Question

25. A car accelerates from rest at constant rate a for some time & decelerates at rate ß. Find the final velocity attained in t sec.: αβ B a. Vrt b. V = t a-B a-B αβ a? c. V =t- a+B d. V =t- a + B​

Answer 1

Answer:

Let maximum velocity=v

Now,v=0+αt

1

Similarly, 0=v−βt

2

From the above equations we get,

t

1

=

α

v

&t

2

=

β

v

t

1

+t

2

=t=

α

v

+

β

v

⇒v=

α+β

αβ

t