25. (a) Certain force acting on a 20 kg mass changes its velocity from 5 m sto 2ms!
Calculate the work done by the force.
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Given : Initial velocity u=5 ms−1
Final velocity v=2 ms−1
From work-energy theorem,
W=ΔK.E
W=21mv2−21mu2
W=21×20×22−21×20×52
⟹W=−210 J
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