Question

25. A circular conductor is made of a uniform wire of
resistance 2 x 10- ohm/metre and the diameter
of this circular conductor is 2 metres. Then the
resistance measured between the ends of the diameter
is (in ohms)
(a) + X 10-3
(b) 2 x 10-
(c) 4 X 10-
(d) 4 x 10-3​

Answer 1

Answer:

The length can be calculated as L=π×D L = π × D , where D is given diameter of 2 m. Therefore, Resistance =2×10−3×2π=4π×10−3Ohms. = 2 × 10 − 3 × 2 π = 4 π × 10 − 3 O h m s .