Question

25. A man sold two radios at Rs.4800 each. On one he gains 20% and on the other he loses 20%.Find the gain or loss percent in the whole transaction.

Answer 1

total s.p=4800*2=9600
first radio
HE SOLD AT GAIN OF 20%
c.p= (4800*100)/120
=4000
second radio
HE SOLD AT loss OF 20%
c.p=(4800*100)/80
     =6000
total cost price=10000
total s.p=9600
loss=400
loss%=(400*100)/10000
loss%=4%
pls mark AS brainliest

Answer 2

Answer:

There is a loss of 4% in the whole transaction.

Step-by-step explanation:

A man sold two radios at 4,800 Rs. each.

Let the cost price of his radio = x

He gains on his first radio = 20%

So, cost price of his first radio = 120% of x = 4,800

                                                  = 1.2x = 4800

                                                  x = $\frac{4800}{1.2}$

                                                  x = 4,000 Rs.

Let the cost price of his second radio = y

He loses on his second radio = 20%

So, cost price of his second radio = 80% of y = 4,800

                                                        = 0.80y = 4800

                                                        y = $\frac{4800}{0.80}$

                                                        y = 6,000 Rs.

Total cost price of both radios = 4000 + 6000 = 10,000 Rs.

Total selling price of both radios = 4800 + 4800 = 9,600 Rs.

Hence selling price is less than cost price, there is a loss.

Loss = 10,000 - 9,600 = 400 Rs.

Loss percentage = $\frac{400}{10000}\times 100$

                            = 4%

There is a loss of 4% in the whole transaction.

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