Physics, asked by prateek3269, 8 months ago

25.
A sphere of radius R carries charge density proportional to the square of the distance from the
center: p= Ar, where A is a positive constant. At a distance of R/2 from the center, the magnitude
of the electric field is :-
(A) A/4118
(B) AR3/40€ (C) AR3/24€
(D) AR/5€​

Answers

Answered by abcdefghi76
2

Answer:

ANSWER

Accordingtoquestion..............chargedensityP=Volumeofspherechargeenclosed=VQ=34πr3QfromGaussLaw:ElectricfieldEatdistancerfromcentre=A.E0Q=A.E0p.V=4πr3p.(34πr3)=3.E0prElectricfi

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