25 a square minus 4 b square + 28 BC - 49 c square
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Answer:
(5a + 2b -7c)(5a-2b+7c)
Step-by-step explanation:
25a²-4b²+28bc-49c²
(5a)²-(4b²-28bc+49c²) ---->*(a-b)²=(a²-2ab+b²)*
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(5a)²-((2b)²-28bc+(7c)²) =(2b + 7c)²
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(5a)²-(2b+7c)²
(5a+2b-7c) (5a-(2b-7c) --->*-1 x -1 =1 , -1 x 1 = 1 *
(5a + 2b -7c)(5a-2b+7c) answer
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