25.(a) State Newton’s second law of motion. Derive, its mathematical expression. (1+2)
(b) A constant force acts on an object of mass 5 KG for duration of 2 second, it increases the velocity of the 3m/s to 7m/s. Find the force acted on the object. 2
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According to Newton's second law of motion, the rete of change of momentum of a body is directly proportional to the force applied on it and the change in moment takes place in the direction in which force is applied...
Equation
Let the force F be applied on a body of mass m for time t due to which it's velocity changes from u to v.
Initial momentum of the body=mu
Final momentum of the body=mv
Change in momentum of the body in t seconds=
mv-mu=m(v-u)
Rate of change of momentum=
Change in momentum/Time=m(v-u)/t
But acceleration a=Change in velocity/time= (v-u)/t
Therefore, rate of change of momentum=
mass × acceleration=m×a
Hope it helps ☺️
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