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a train starting from rest moves with a uniform acceleration of 0.2m/s^2 for 5 minutes calculate the speed acquired and the distance travelled in the this time
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s=u+at
=0+0.2*300
=60
therefore speed of train is 60m/s
distance= speed *time
=60*300
=18000
therefore distance covered by train is 18000m
=0+0.2*300
=60
therefore speed of train is 60m/s
distance= speed *time
=60*300
=18000
therefore distance covered by train is 18000m
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