25. A vertical electrical pole of 20 m. long casts a shadow of 12 m. long on the ground. At the
same time a building casts the shadow of 48 m long on the ground. Determine the height of
the building
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Given:
A vertical electrical pole of 20 m. long casts a shadow of 12 m.
To find:
The height of the other building whose shadow is 48 m long.
Solution:
1) At the same time if two or more objects cast the shadow by the Sun and at that moment the sun is fixed at a point so the ratio of the height of the object and height of the shadow is always proportional to the other one.
2) Height of pole = 20 m.
Height of shadow of pole = 12m.
Let the height of building = X m
Height of the shadow of the building = 48 m.
as per the rule,
- 20/12 = X/48
- X = 20/12 ×48
- X = 20×4
- X = 80m.
The height of the building is 80 m.
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