Question

25. ABCD is the cross-section of a metal container in a paint factory P Q is R 2.4-5 A B مم.1 D С € 1.6 If AB = 2.4 m, DC = 1.6 m, BQ = CR = 1.2 m and height of the container is 1.1 m, find (i) the volume of paint in the container. (ii) the cost of paint at 40 per litre. [1 m² = 1000 litres]
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Answer 1

Answer:

$2.64 m^3$

Step-by-step explanation:

An area is projected onto the plane when a plane slices through a solid object. The axis of symmetry is then perpendicular to that plane. The cross-sectional area refers to its projection. Example: For a cube with a volume of 27 cm3, determine the cross-sectional area of a plane perpendicular to the base. In contrast, the cross-sectional area is the area obtained when splitting the identical item into two. Cross sectional area refers to the size of that specific cross section.

We have,

$A B C D$ is the cross-section of a metal container in a paint factory. If $A B=2.4 \mathrm{~m}, D C=1.6 \mathrm{~m}, B Q=C R=1.2 \mathrm{~m}$  and height of the container is $1.1 \mathrm{~m}$,

Area of cross-section $A B C D$ is $\frac{1}{2}(A B+D C) \times C M$

$\begin{aligned}& =\quad 121.6+2.4 \times 1.1 \quad \vee \\& =2.2 \mathrm{~m}^2 \\&\end{aligned}$

Now the volume of paint in the container = Area of cross-section $\times$  Length of metal container

$=2.2 \times 1.2=2.64 \mathrm{~m}^3$

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