Chemistry, asked by shaahid, 5 months ago

25. Assertion : Al(OH)3 is insoluble in NH4OH but soluble in NaOH.
Reason: NaOH is strong alkali.

Answers

Answered by shivansht2005

0

Both assertion and reason are correct, but the reason is not the correct explanation of the assertion, as

Al(OH)3 forms soluble complex with NaOH and not with NH4OH.

Al(OH)3+OH−→[Al(OH)4]−

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