Question

25. Beso is a currency which is available only in three
denominations - 1 Beso, 5 Besos and 20 Besos.
A person had to settle a bill which amounted to
49 Besos. If he uses at least one note of each
denomination, in how many ways can he settle the bill?​

Answer 1

Answer:

The answer is 6.

Step-by-step explanation:

The second restriction is quite interesting. What does it mean is that a20, a5, and a1 must be used, therefore the question is equivalent to asking how many ways there are to settle a 49-26=23 beso bill with zero or no restrictions.

If a 20 is used, there is only one way. That is(20-1-1-1)

If a 20 is not used, then either 0,1,2,3, or 4 5's can be used. For each of these there is only one way.

Therefore there are total 6 ways.

Answer 2

Answer:

6

Step-by-step explanation:

Let a = 1 Beso, b = 5 Besos and c = 20 Besos

Then, According to the question:

a+5b+20c = 49

Now, since he uses at least 1 note,

therefore, a + b +c >= 1

If c=1, a+5b = 29

c = 2, a + 5b = 9

c = 3, a + 5b = - 11 which is negative(Not possible)

Therefore c can be 1 or 2

Case 1:

when c = 1, a + 5b = 29

(a,b) = (24,1), (19,2), (14,3), (9,4), (4,5) I.e 5 possible ways

Case 2:

a + 5b = 9

(a,b) = (4, 1)

Therefore (a,b) has total 6 possible ways.