Question

25 buses are running between two places P and Q. In how many ways can a person go from P to Q and
return by a different bus?
Select one:
O a. 600
O b. 676
O c. 576
O d. 625​

Answer 1

Answer:

Option A

Step-by-step explanation:

He can go in any of the 25 buses (25 ways).

Since he cannot come back in the same bus, he can return in 24 ways.

Total number of ways =25×24=600

Answer 2

Answer:

Heya mate your answer

Step-by-step explanation:

Let the  25  buses be  b1,b2,b3,...,b25  

Let these buses be the elements of Bus set  B  

If a person goes from  P  to  Q  by bus  b1  he can return by any of  b2,b3,…,bn  

Similarly for  b2,b3  and so on

Thus, for any bus  bi∈B , person can return by any of  B−bi  buses, i.e. total 24 combinations

There are  25  buses , therefore total number of combinations are  24×25=600  

Hence there are  600  ways, in which a person can go from  P  to  Q  and return by a different bus.

Hope that helps :)