25 CC of a gaseous mixture of CH4 and C2H4 required 66cc of oxygen for complete combustion . what is the composition of the mixture by volume.
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Answer:
Volume of mixture =30 mL, CH
4
:C
2
H
4
::a:b
∴ Volume of CH
4
=
(a+b)
30a
and C
2
H
4
=
(a+b)
30a
CH
4
+2O
2
→CO
2
+2H
2
O
a+b
30a
0 Initial
0
(a+b)
30a
Final
C
2
H
4
+3O
2
→2CO
2
+2H
2
O
a+b
30b
0 Initial
0
(a+b)
2×30b
Final
∴
(a+b)
30a
+
a+b
60b
=40
∴10a=20b
∴
b
a
=
1
2
∴CH
4
=20mL,C
2
H
4
=10mL
If ratio is reversed i.e., CH
4
=10mL,C
2
H
4
=20mL
Then, CO
2
formed=10+40=50mL
Explanation:
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