Question

25 cm
concave
mirror
14 cm
what
10 The object 4cm in size as placed at
in front of
of focal
denght
distance from the
mirror
screen
be placed in order
obtain a sharp image & find the
size of the image.
should
nature
to
and​

Answer 1

Answer:

50cm distance

on image

thanks for a nice questions

Answer 2

Explanation:

Hello Dear.

Here is the answer---

Height of the Object(H₀) = 4 cm.

Object Distance(u) = 25 cm.(negative)

Focal Length = 15 cm.(negative)

Using the Mirror's Formula,

\frac{1}{f} = \frac{1}{v} + \frac{1}{u}

f

1

=

v

1

+

u

1

⇒ \frac{1}{-15} = \frac{1}{-25} + \frac{1}{v}

−15

1

=

−25

1

+

v

1

⇒ v = - 37.5 cm.

Thus, the image is formed behind the mirror. Since the Distance is Negative, thus the Image is Real.

Thus, Screen is to be placed at a Distance of 37.5 cm behind the Mirror.

Now, Magnification = H₁/H₀

Also, Magnification = -v/u

∴ H₁/H₀ = -v/u

⇒ H₁/4 = - (-37.5)/25

⇒ H₁ = 37.5 × 4/25

⇒ H₁ = 150/25

⇒ H₁ = 6 cm.

Since, the Size of the Image is greater than the size of the Object, thus the image is Magnified.

Hence, Characteristics of the Images are---

Real, Inverted and Magnified.

Hope it helps.

And Please mark me brainliest.