Question

25. Construct a triangle ABC, with m_A = 70°, m_B = 50° and
AC = 3cm. (3 marks)​

Answer 1

Answer:

What is the construction that in a triangle ABC m of B=60 degrees, AC=6.5cm, and AX=5?

In ∆ABC, AB=c=3 AC=b=4 & <BAC=60° BC=a=?

Therefore,by applying cosine rule we get

(BC)^2=(AC)^2+(AB)^2–2×(AB)×(AC)×cos(BAC)

a^2=b^2+c^2–2×b×c×cos(60°)

a^2=(3)^2+(4)^2–2×3×4×0.5

a^2=9+16-12

a^2=13

a=√13

Hence length of side BC is √13

Answer 2

Answer:

Prove that the ratio of the areas of two similar triangles is equal to the square of theratio of their corresponding sides.

two circles of same eadie are _______??

prove that 2.(a sin^2C/2+c sin^2A/2)=a+c-b