25 cubical blocks of wood were painted on all sides .if the total cost of painting at the rate of ₹8 per cm was ₹30000 find the length of edge of a block
Answers
Answered by
60
Cost of painting 25 blocks = 30000
Cost of painting 1 block = 30000/25
= 1200
Area of 1 cubical block = 1200/8
= 150
Total surface area of cube = 6a^2
150/6 = a^2
25 = a^2
a = 5
Therefore edge of 1 cube = 5.
Hope it helps.
If you satisfied mark it brainliest.
Cost of painting 1 block = 30000/25
= 1200
Area of 1 cubical block = 1200/8
= 150
Total surface area of cube = 6a^2
150/6 = a^2
25 = a^2
a = 5
Therefore edge of 1 cube = 5.
Hope it helps.
If you satisfied mark it brainliest.
Answered by
17
total cost is 30000
total blocks are 25
area is 30000÷25=1200 cm square
area of one block is 1200÷8 is 150
surface area of cube is 150÷6 is 25
side is square root of 25 is 5
so each side is 5 cm
total blocks are 25
area is 30000÷25=1200 cm square
area of one block is 1200÷8 is 150
surface area of cube is 150÷6 is 25
side is square root of 25 is 5
so each side is 5 cm
Similar questions