Question

25. Find a quadratic polynomial whose zeros are 3/√2 and -1/√2​

Answer 1

Answer:

$2 {x}^{2} - 2 \sqrt{2} x - 3$

Step-by-step explanation:

$The \: quadratic \: polynomial \: is:- \\ {x}^{2} - ( \frac{3}{ \sqrt{2}} + ( - \frac{1}{ \sqrt{2}} ))x + (\frac{3}{ \sqrt{2}} \times( - \frac{1}{ \sqrt{2}} )) \\ = {x}^{2} - \frac{2}{ \sqrt{2} } x - \frac{3}{2} \\ = {x}^{2} - \sqrt{2} x - \frac{3}{2} \\ = 2 {x}^{2} - 2 \sqrt{2} x - 3$

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