Question

25. Find p (0), p (1) and p (2) for the polynomial of p(x) = (x - 1) (x + 1)?​

Answer 1

Step-by-step explanation:

= p(X)= (x-1)(x+1)

(i)=p(0)=(0-1)(0+1)

= (0^2 - 1^2)

=(0-1).

= -1

(ii)=p(1)=(1-1)(1+1)

=(1^2-1^2)

= (1-1)

= 0

(iii)=p(2)=(2-1)(2+1)

= (2^2-1^2)

= (4-1)

= 3