25) Find the area of a triangle two sides of which are 8 cm and 11 cm and the perimeter is
32 cm
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Answer:
ans in the pic .......
Step-by-step explanation:
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Step-by-step explanation:
perimeter=a+b+c
32=8+11+c
32-19=c
c=13
s=p/2
32/2
= 16
(s-a) = 16-8=8
(s-b)= 16-11=5
(s-c)=16-13=3
Area= √s(s-a)(s-b)(s-c)
√16×8×5×3
√8×2×8×5×3
=8√30 cm²
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