Question

25. Find the area of shaded region in the figure 4 cm 3 cm 12 cm
​

Answer 1

Answer:

In ΔABC,

Angle in a semicircle, ∠C=90

o

Therefore, by Pythagoras theorem

BC

2

+AC

2

=AB

2

BC

2

+12

2

=13

2

BC

2

=169−144=25

BC=5

Area of shaded region = Area of semicircle – Area of triangle

=

2

1

πr

2

−

2

1

bh

=

2

1

×3.14×(

2

13

)

2

−

2

1

×5×12

=

2×4

3.14×13×13

−30

Area of shaded region =36.39 cm

2

.