Question

25. Find the greatest number which divides 615 and 963, leaving the remainder 6 in each case.
26. Find the greatest number which divides 2011 and 2623, leaving remainders 9 and 5
respectively.
27. Find the greatest number that will divide 445, 572 and 699, leaving remainders 4, 5, 6
respectively.​

Answer 1

25.Therefore the greatest number that divides 615 and 963 by leaving remainder 6 is 87.

26.So, the greatest number which divides 2011 and 2623 leaving remainders 9 and 5 respectively is 154.

27.So, the greatest number which divides 445, 572 and 699 leaving remainders 4, 5 and 6 respectively is 63.

Answer 2

here is your answer

1. In order to find the largest number which divides 615 and 963 leaving remainder 6

we get

615-6=609

963 - 6 = 957

So, the required number = HCF of 609 and 957

By resolving the required number into prime factors we get

609 = 3 ×7×29

957 = 3 × 11 × 29

Therefore, the HCF of 609 and

957 = 29 × 3 = 87

Hence, the greatest number which divides 615 and 963 leaving remainder 6 in each case is 87 .

2. one is in picture

3 . one is in picture

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