25 Find the probability that a large year,selected at random
contain 53 Sundays.
Answers
Answer:
2/7
Step-by-step explanation:
leap year has 53 sundays
leap year= 365 days and 1 day
total outcomes= 7
s. s= Sunday Monday, Monday Tuesday,Tuesday Wednesday,Wednesday Thursday,Thursday Friday,Friday Saturday,Saturday sunday
probability = 2/7
Answer:
leap year has 366 days with 52 weeks and 2 days
Now, 52 weeks contains 52 Sundays.
remaining two days can be:(i) Sunday and Monday, (ii) Monday and Tuesday, (iii) Tuesday and Wednesday, (iv) Wednesday and Thursday, (v) Thursday and Friday, (vi) Friday and Saturday,(vii) Saturday and Sunday
Let E be the event of getting a leap year with 53 Sundays
Total cases = 7
Number of favorable case, i.e. getting 53rd sunday = 2 [Sunday and Monday / Saturday and sunday]
∴ P (a leap year having 53 Sundays) = P (E) = 2/7