Question

25. Find the value of p for which the points (-5, 1), (1, p)
and (4, -2) are collinear.​

Answer 1

Step-by-step explanation:

If the points are collinear then the area will be 0.

Area=0

$0 = \frac{1}{2} (x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2))$

=

0=½[(-5)(p-(-2))+1(-2-1)+4(1-p)]

0=½[(-5)(p+2)+(-3)+4(1-p)]

0=½[-5p-10-3+4-4p]

0=-9p-13+4

0=-9p-9

9=-9p

9/-9=

-1=p.

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Answer 2

Answer:

answer attached in photo